R语言中比较出名的矩阵
iris3
state.x77 # 美国五十个州八个指标12
矩阵其实就是给向量加一个维度
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1、创建矩阵
> x <- 1:20> x [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20# 定义一个对象m， 用来存储矩阵，第二个参数指定行数，第三个参数用来指定列数，可以省略，直接写4，5> m <- matrix(x,nrow = 4,ncol = 5)> m [,1] [,2] [,3] [,4] [,5][1,] 1 5 9 13 17[2,] 2 6 10 14 18[3,] 3 7 11 15 19[4,] 4 8 12 16 20# 此为上述代码的简写> m <- matrix(x,4,5)> m [,1] [,2] [,3] [,4] [,5][1,] 1 5 9 13 17[2,] 2 6 10 14 18[3,] 3 7 11 15 19[4,] 4 8 12 16 20# 行和列必须要满足条件 4行6列会报错，超过了限制> m <- matrix(x,nrow = 4,ncol = 6)Warning message:In matrix(x, nrow = 4, ncol = 6) :
data length [20] is not a sub-multiple or multiple of the number of columns [6]# > matrix(x,4,4)
[,1] [,2] [,3] [,4][1,] 1 5 9 13[2,] 2 6 10 14[3,] 3 7 11 15[4,] 4 8 12 16# 行和列要有一个满足条件，否则会报错 报错原因，因为20不是3的整数倍> matrix(x,3,3)
[,1] [,2] [,3][1,] 1 4 7[2,] 2 5 8[3,] 3 6 9Warning message:In matrix(x, 3, 3) :
data length [20] is not a sub-multiple or multiple of the number of rows [3]# 只给一个行或者列会自动分配，矩阵是按照列进行分配的> matrix(x,4)
[,1] [,2] [,3] [,4] [,5][1,] 1 5 9 13 17[2,] 2 6 10 14 18[3,] 3 7 11 15 19[4,] 4 8 12 16 20# byrow=TURE按行排列，否则按列排列> m <- matrix(x,nrow = 4,ncol = 5,byrow = TRUE)> m [,1] [,2] [,3] [,4] [,5][1,] 1 2 3 4 5[2,] 6 7 8 9 10[3,] 11 12 13 14 15[4,] 16 17 18 19 20# 修改行和列的名称> rnames <- c("R1","R2","R3","R4")> cnames <- c("C1","C2","C3","C4","C5")> dimnames(m)=list (rnames,cnames)> m C1 C2 C3 C4 C5R1 1 2 3 4 5R2 6 7 8 9 10R3 11 12 13 14 15R4 16 17 18 19 20# dim()函数可以显示向量的维数> dim(x)NULL# 为向量添加函数构建矩阵> dim(x) <- c(4,5)> x [,1] [,2] [,3] [,4] [,5][1,] 1 5 9 13 17[2,] 2 6 10 14 18[3,] 3 7 11 15 19[4,] 4 8 12 16 20123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990![]()
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2、创建数组
# 三维数组，可以理解为一个长宽高分别为2，2，5的矩阵> dim(x) <- c(2,2,5)> x, , 1
[,1] [,2][1,] 1 3[2,] 2 4, , 2
[,1] [,2][1,] 5 7[2,] 6 8, , 3
[,1] [,2][1,] 9 11[2,] 10 12, , 4
[,1] [,2][1,] 13 15[2,] 14 16, , 5
[,1] [,2][1,] 17 19[2,] 18 20# Creating an array> x <- 1:20> dim(x) <- c(2,2,5)> dim1 <- c("A1", "A2") # 行> dim2 <- c("B1", "B2", "B3") # 列> dim3 <- c("C1", "C2", "C3", "C4") # 给几个值就为几维数组# dimnames用来定义每个维度的标签> z <- array(1:24, c(2,3,4), dimnames=list(dim1, dim2, dim3))> z, , C1
B1 B2 B3A1 1 3 5A2 2 4 6, , C2
B1 B2 B3A1 7 9 11A2 8 10 12, , C3
B1 B2 B3A1 13 15 17A2 14 16 18, , C4
B1 B2 B3A1 19 21 23A2 20 22 2412345678910111213141516171819202122232425262728293031323334353637383940414243444546474849505152535455565758596061626364656667![]()
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3、通过索引访问矩阵
# 4x5的矩阵m> m <- matrix(x,nrow = 4,ncol = 5)> m [,1] [,2] [,3] [,4] [,5][1,] 1 5 9 13 17[2,] 2 6 10 14 18[3,] 3 7 11 15 19[4,] 4 8 12 16 20# 访问第一行第二列的元素> m[1,2][1] 5# 访问第一行二，三，四列的元素> m[1,c(2,3,4)][1] 5 9 13# 访问矩阵一个子集> m[c(2,4),c(2,3)]
[,1] [,2][1,] 6 10[2,] 8 12# 访问第二行> m[2,][1] 2 6 10 14 18# 访问第二列> m[,2][1] 5 6 7 8# 访问对应的行> m[2] [1] 2# 去除第一行再取第二列> m[-1,2][1] 6 7 81234567891011121314151617181920212223242526272829303132333435363738
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4、通过名称访问矩阵
> dimnames(m)=list (rnames,cnames) > m C1 C2 C3 C4 C5R1 1 5 9 13 17R2 2 6 10 14 18R3 3 7 11 15 19R4 4 8 12 16 20# 此行出错> m["C1","C2"]Error in m["C1", "C2"] : subscript out of bounds# 通过行名列名访问元素> m["R1","C2"][1] 5# 出错部分> m["R1"][1] NA> m["C1"][1] NA> m[,"R1"]Error in m[, "R1"] : subscript out of bounds# 想要访问列的名字，访问列> m["R1",]C1 C2 C3 C4 C5
1 5 9 13 17 # 想要访问行的名字 ，访问行> m[,"C1"]R1 R2 R3 R4
1 2 3 4 123456789101112131415161718192021222324252627282930313233
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5、矩阵的运算
此部分为矩阵的一些写法以及计算技巧
实现矩阵的转置，行变列，列变行
> a <- matrix(1:12,nrow = 3,ncol = 4)
> a
[,1] [,2] [,3] [,4]
[1,] 1 4 7 10
[2,] 2 5 8 11
[3,] 3 6 9 12
# 行列互换
> t(a)
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 4 5 6
[3,] 7 8 9
[4,] 10 11 121234567891011121314
> a <- b <- matrix(1:12,nrow = 3,ncol = 4)
> a+b
[,1] [,2] [,3] [,4]
[1,] 2 8 14 20
[2,] 4 10 16 22
[3,] 6 12 18 24
> a-b
[,1] [,2] [,3] [,4]
[1,] 0 0 0 0
[2,] 0 0 0 0
[3,] 0 0 0 01234567891011
> a <- matrix(1:12,nrow = 3,ncol = 4)
> b <- matrix(1:12,nrow = 4,ncol = 3)
> a%*%b 线代矩阵相乘
[,1] [,2] [,3]
[1,] 70 158 246
[2,] 80 184 288
[3,] 90 210 3301234567
求对角线，diag()函数
> a <- matrix(1:16,nrow = 4,ncol = 4)
> a
[,1] [,2] [,3] [,4]
[1,] 1 5 9 13
[2,] 2 6 10 14
[3,] 3 7 11 15
[4,] 4 8 12 16
# 返回对角线
> diag(a)
[1] 1 6 11 16
# 对角线矩阵
> diag(diag(a))
[,1] [,2] [,3] [,4]
[1,] 1 0 0 0
[2,] 0 6 0 0
[3,] 0 0 11 0
[4,] 0 0 0 16
# 产生一个四阶的单位矩阵
> diag(4)
[,1] [,2] [,3] [,4]
[1,] 1 0 0 0
[2,] 0 1 0 0
[3,] 0 0 1 0
[4,] 0 0 0 1123456789101112131415161718192021222324252627
solve()函数
# 先使用rnorm函数随机生成16个随机数，并创建矩阵
> a <- matrix(rnorm(16),4,4)
> a
[,1] [,2] [,3] [,4]
[1,] 0.19496384 -1.32876618 0.8009854 0.1090159
[2,] 0.83996855 -1.31302374 0.4815483 -0.2333306
[3,] -1.71094415 0.03186264 -0.5280415 2.3790375
[4,] -0.03161188 0.85040187 0.4736652 -0.5227957
# solve()函数可以直接求逆
> solve(a)
[,1] [,2] [,3] [,4]
[1,] -2.3313965 3.2960835 0.7418279 1.418528
[2,] -1.1575768 1.2092526 0.4392610 1.217815
[3,] 0.1181362 0.8574405 0.4068229 1.493238
[4,] -1.6349574 2.5445791 1.0382558 1.33529212345678910111213141516
solve()函数还能解线性方程
eg: ax=b
> a <- matrix(rnorm(16),4,4)
> a
[,1] [,2] [,3] [,4]
[1,] 1.2319870 -0.1801956 0.1470676 0.01413551
[2,] -0.2092927 0.2776381 1.0411766 0.44004831
[3,] 1.3762975 -0.6371769 -1.3026650 -1.20290275
[4,] 0.1149844 0.4075077 0.1193776 -0.21052398
> b <- c(1:4)
> b
[1] 1 2 3 4
> solve(a,b)
[1] 0.894783 3.750849 4.723690 -8.5724731234567891011121314
用来求矩阵的特征值与特征向量
> a <- diag(4)+1
> a
[,1] [,2] [,3] [,4]
[1,] 2 1 1 1
[2,] 1 2 1 1
[3,] 1 1 2 1
[4,] 1 1 1 2
> a.e = eigen(a,symmetric = T)
> a.e
eigen() decomposition
$values
[1] 5 1 1 1
$vectors
[,1] [,2] [,3] [,4]
[1,] -0.5 0.8660254 0.0000000 0.0000000
[2,] -0.5 -0.2886751 -0.5773503 -0.5773503
[3,] -0.5 -0.2886751 -0.2113249 0.7886751
[4,] -0.5 -0.2886751 0.7886751 -0.211324912345678910111213141516171819
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6、添加
colSums(m) # 求矩阵每一列的和
rowSums(m) # 求矩阵每一行的和
colMeans(m) # 求矩阵每一列的平均值
rowMeans(m) # 求矩阵每一行的平均值
n <- matrix (1:9,3,3) # 3行3列的矩阵
t <- matrix (2:10,3,3) # 3行3列的矩阵
n*t # 矩阵的内积
n%*%t # 矩阵的外积123456789101112
转载自：CSDN 作者：不温卜火
原文链接：https://blog.csdn.net/qq_16146103/article/details/105410413
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